A) 6
B) 7
C) 8
D) 9
Correct Answer: B
Solution :
[b] Let the fraction be \[\frac{x}{y}\] |
Then, according to question, |
\[\frac{x+1}{y+1}=\frac{4}{5}\,\,\,\Rightarrow \,\,\,5x+5=4y+4\] |
\[5x-4y=-1\] (1) |
and \[\frac{x-5}{y-5}=\frac{1}{2}\] |
\[2x-10=y-5\] |
\[2x-y=5\] ...(2) |
On multiplying eq. (1) by 2 and eq. (2) by 5 and then subtracting eq. (2) from eq. (1), we get |
\[y=9\] |
Substituting the value of y in eq. (1), we get |
\[5x-4\times 9=-1\] |
\[5x=-1+36\,\,\,\Rightarrow x=7\] |
Hence, Fraction \[=\frac{7}{9}\] |
Therefore, numerator of this fraction is 7. |
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