A) \[(2,4)\]
B) \[(4,2)\]
C) \[(-2,2)\]
D) \[(2,2)\]
Correct Answer: D
Solution :
[d] Given, \[2x+y-6=0\]and \[4x-2y-4=0\] |
or \[y=6-2x\]and \[2x-2=y\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,6-2x=2x-2\,\,\Rightarrow \,\,4x=8\Rightarrow x=2\] |
and \[y=6-2\times 2=6-4=2\] |
So, required solution is \[(2,2)\]. |
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