A) 39 and 26
B) 39 and 41
C) 39 and 13
D) None of these
Correct Answer: C
Solution :
Let the two numbers be x and\[y\text{ }\left( x>y \right)\]. |
According to the question, |
\[x-y=26\] ...(i) |
and \[x\text{ }=\text{ }3y\] ...(ii) |
On substituting the value of x from Eq. (ii) in Eq. (i), we get |
\[3y-y=26\] |
\[\Rightarrow \,\,\,2y=26\] |
\[\Rightarrow \,\,\,y=13\] |
On substituting y = 13 in Eq. (ii), we get |
\[x=3\times 13\] |
\[\Rightarrow \,\,x=39\] |
Hence, the two numbers are 39 and 13. |
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