A) \[a+b\]
B) \[a-b\]
C) 0
D) 1
Correct Answer: B
Solution :
[b] Given equations are |
\[ax+by={{a}^{2}}-{{b}^{2}}\] ...(1) and \[bx+ay=0\] ...(2) |
On adding both equations, we get |
\[(ax+by)+(bx+ay)={{a}^{2}}-{{b}^{2}}\] |
\[\Rightarrow \,\,\,\,\,(a+b)x+(a+b)={{a}^{2}}-{{b}^{2}}\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,(a+b)\,\,(x+y)=(a+b)\,(a-b)\] |
Hence, \[x+y=a-b\] |
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