A) \[1/2\]
B) \[-1/2\]
C) \[2\]
D) \[-2\]
Correct Answer: C
Solution :
[c] Given equations of lines are \[3x-y+8=0\] |
and \[6x-ky+16=0\] |
Here, \[{{a}_{1}}=3,\,{{b}_{1}}=-1,\,{{c}_{1}}=8\] |
and \[{{a}_{2}}=6,\,\,{{b}_{2}}=-k,\,{{c}_{2}}=16\] |
These equations represent coincident lines if |
\[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}=\frac{{{c}_{1}}}{{{c}_{2}}}\Rightarrow \frac{3}{6}=\frac{-1}{-k}=\frac{8}{16}\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\frac{1}{k}=\frac{1}{2}\Rightarrow k=2\] |
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