A) one solution
B) two solutions
C) no solution
D) many solutions
Correct Answer: A
Solution :
[a] \[{{a}_{1}}=2,\,\,{{b}_{1}}=-3,\,\,{{c}_{1}}=-1\] |
\[{{a}_{2}}=3,\,\,{{b}_{2}}=-2,\,\,{{c}_{2}}=-4\] |
\[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{2}{3},\,\frac{{{b}_{1}}}{{{b}_{2}}}=\frac{3}{2}\,\,\,\,\,\,\,\,\Rightarrow \,\,\,\,\,\frac{{{a}_{1}}}{{{a}_{2}}}\ne \frac{{{b}_{1}}}{{{b}_{2}}}\] |
\[\therefore \] Unique solution of one solution. |
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