A) \[36,12\]
B) \[30,10\]
C) \[40,14\]
D) \[33,11\]
Correct Answer: A
Solution :
[a] Let the two numbers be x and y where \[x>y\]. |
According to the question, |
\[x-y=24\] ...(1) |
and \[x=3y\Rightarrow x-3y=0\] ...(2) |
Subtracting eq. (2) from eq.(1), we get |
\[2y=24\Rightarrow y=12\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,x=3y=3\times 12=36\] |
You need to login to perform this action.
You will be redirected in
3 sec