A) \[12m,\,9m\]
B) \[17m,\,14m\]
C) \[15m,\,12m\]
D) \[14m,\,11m\]
Correct Answer: C
Solution :
[c] Let length of the room is x m and breadth is y m. |
Then, \[x=y+3\,\,\Rightarrow \,\,\,x-y=3\] ...(1) |
and \[(x+3)\,\,(y-2)=xy\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,-2x+3y=6\] ...(2) |
Multiplying eq. (1) by 2, we get |
\[2x-2y=6\] ...(3) |
On adding eqs. (2) and (3), we get \[y=12\] |
Substituting \[y=12\]in eq. (1), we get |
\[x=12+3=15\] |
Hence, the length and breadth of the room are 15 m and 12 m respectively. |
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