A) True
B) False
C) Can't say
D) Partially true/false
Correct Answer: A
Solution :
(True) Put 1 in \[{{x}^{2}}-3x+2\] \[1-3+2=0\] 1 satisfy the equation Put 2 in \[{{x}^{2}}-3x+2\] \[4-3\times 2+2=0\]You need to login to perform this action.
You will be redirected in
3 sec