A) True
B) False
C) Can't Say
D) Partially True/False
Correct Answer: A
Solution :
p(x)=0 |
\[x-1=0\] |
\[x=1\] |
\[g\left( x \right)={{x}^{2}}-2x+1\] |
According to question, |
p (x) is a factor of g (x) |
\[g\text{ }\left( 1 \right)=0\] |
\[g\left( 1 \right)=1-2+1=0\] |
So, p(x) is a factor of g(x) |
You need to login to perform this action.
You will be redirected in
3 sec