A) -2 and -3
B) 3 and 4
C) 3 and 2
D) 2 and 1
Correct Answer: A
Solution :
| Given, |
| Quadratic polynomial \[\left( {{x}^{2}}+5x+6 \right)\] |
| We have to find the zeroes of \[{{x}^{2}}+5x+6\] |
| By factorization, |
| \[{{x}^{2}}+3x+2x+6=0\] |
| \[x\left( x+3 \right)+2\left( x+3 \right)=0\] |
| \[\left( x+3 \right)\left( x+2 \right)=0\] |
| \[x=-3,\,x=-2\] |
| Hence, zeroes \[x=-3,\,x=-2\] |
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