A) -1
B) 0
C) 1
D) 2
Correct Answer: A
Solution :
\[\alpha\] and \[\beta\]are the zeroes of \[2{{y}^{2}}+7y+5\] |
We know that, \[\alpha +\beta =-\frac{b}{a}=-\frac{7}{2}\] |
\[\alpha \,.\,\beta =\frac{c}{a}=\frac{5}{2}\] |
\[\Rightarrow \,\left( \alpha +\beta \right)+\left( \alpha \,.\,\beta \right)=-\frac{7}{2}+\frac{5}{2}=\frac{-7+5}{2}=-1\] |
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