A) 21
B) 12
C) 9
D) 8
Correct Answer: B
Solution :
| \[\alpha \] and \[\beta \]are zeroes of \[{{x}^{2}}-7x+k\] |
| We know that, |
| Sum of zeroes \[\left( \alpha +\beta \right)=\frac{-b}{a}=\frac{7}{1}\] ...(i) |
| \[\alpha \,.\,\beta =\frac{c}{a}=k\] |
| \[\alpha -\beta =1\] [Given] ...(ii) |
| From Eqs. (i) and (ii) we get \[\alpha =4\] and \[\beta =3\] |
| \[k=\alpha \,.\,\beta \] |
| \[k=4\times 3=12\] |
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