A) 0
B) 2
C) \[\frac{5}{2}\]
D) \[\frac{1}{2}\]
Correct Answer: C
Solution :
| Given, \[f\left( x \right)=a{{x}^{2}}-3\left( a-1 \right)x-1\] |
| and 2 is zero of \[f\left( x \right)\], |
| \[f\left( 2 \right)=0\] |
| \[f\left( 2 \right)=a{{\left( 2 \right)}^{2}}-3\left( a-1 \right)\times 2-1\] |
| \[0=4a-6a+6-1\] |
| \[2a=5\] |
| \[a=\frac{5}{2}\] |
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