A) -1
B) 1
C) -9
D) 9
Correct Answer: A
Solution :
[a] Let the third zero of the polynomial \[{{x}^{3}}+{{x}^{2}}-9x-9\] be \[\alpha \]. |
Now, sum of zeroes \[=\frac{-1}{1}=-1\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,3+(-3)+\alpha =-1\Rightarrow \alpha =-1\] |
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