A) \[-\frac{3}{4}\]
B) \[\frac{3}{4}\]
C) \[\frac{4}{3}\]
D) \[-\frac{4}{3}\]
Correct Answer: D
Solution :
[d] Let \[\alpha \] and \[\beta \] be the zeroes of polynomial \[k{{x}^{2}}+4x+3k\]According to question, |
\[\alpha +\beta =\alpha \beta \Rightarrow -\frac{4}{k}=\frac{3k}{4}\Rightarrow -\frac{4}{k}=3\Rightarrow k=-\frac{4}{3}\] |
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