A) \[\alpha +\beta =\alpha \beta \]
B) \[\alpha +\beta >\alpha \beta \]
C) \[\alpha +\beta <\alpha \beta \]
D) \[\alpha +\beta +\alpha \beta =0\]
Correct Answer: A
Solution :
| [a] Since \[\alpha ,\beta \] are the zeroes of \[2{{x}^{2}}+8x-8\] |
| \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\alpha +\beta =-\frac{8}{2}=-4\]and \[\alpha \beta =-\frac{8}{2}=-4\] |
| Hence, \[\alpha +\beta =\alpha \beta \] |
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