A) \[-\frac{d}{a}\]
B) \[\frac{c}{a}\]
C) \[-\frac{b}{a}\]
D) \[\frac{b}{a}\]
Correct Answer: C
Solution :
[c] The given polynomial is \[a{{x}^{3}}+b{{x}^{2}}+cx+d.\] |
Now, two of the zeroes of given polynomial are equal to zero. |
[Given] |
Let the third zero be \[\alpha \]. |
\[\therefore \] Sum of zeroes \[=0+\alpha =-\frac{b}{a}\Rightarrow \alpha =-\frac{b}{a}\] |
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