A) \[{{x}^{2}}-3x+5\]
B) \[{{x}^{2}}-6x+7\]
C) \[{{x}^{2}}-7x+6\]
D) \[{{x}^{2}}-8x+12\]
Correct Answer: B
Solution :
Sum of zeroes \[=3+\sqrt{2}+3-\sqrt{2}=6\] |
Product of zeroes \[=\left( 3+\sqrt{2} \right)\left( 3-\sqrt{2} \right)\] |
= 9 - 2 = 7 The quadratic polynomial is |
\[={{x}^{2}}\] - (sum of zeroes) x + product of zeroes |
\[={{x}^{2}}-6x+7\] |
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