A) \[0,\pm 2\]
B) \[0,\pm 1\]
C) \[0,\pm 3\]
D) \[0,\pm 4\]
Correct Answer: B
Solution :
[b] Let \[f(x)={{x}^{3}}-x\] |
The zeroes of the polynomial is given by, \[f(x)=0\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,{{x}^{3}}-x=0\Rightarrow x({{x}^{2}}-1)=0\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,x(x-1)(x+1)=0\Rightarrow x=0,\,1,-1\] |
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