A) \[{{x}^{2}}+5x+6\]
B) \[{{x}^{2}}-5x+6\]
C) \[{{x}^{2}}-5x-6\]
D) \[-{{x}^{2}}+5x+6\]
Correct Answer: A
Solution :
| Let \[\alpha\] and \[\beta\] are the zeroes of quadratic polynomial |
| \[\therefore\] Sum of zeroes, \[\alpha +\beta =-5\] and product of zeroes, \[\alpha \beta =6\] [given] |
| Now, required polynomial |
| \[={{x}^{2}}\]- (sum of zeroes) x + product of zeroes |
| \[={{x}^{2}}-\left( -5 \right)x+6\] |
| \[={{x}^{2}}+5x+6\] |
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