A) \[\frac{1}{2}\]
B) \[-\frac{1}{2}\]
C) \[\frac{7}{2}\]
D) \[-\frac{7}{2}\]
Correct Answer: B
Solution :
| [b] Let \[\alpha ,\beta ,\gamma \] be the zeroes of the polynomial |
| \[f(x)=2{{x}^{3}}+6{{x}^{2}}-4x+7.\] |
| Now, product of zeroes \[=-\frac{7}{2}\] |
| \[\Rightarrow \,\,\,\,\,\,\alpha \beta \gamma =-\frac{7}{2}\Rightarrow 7\times \gamma =-\frac{7}{2}\] [Given, \[\alpha \beta =7\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\gamma =-\frac{1}{2}\] |
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