A) 0
B) 1
C) 4
D) 5
Correct Answer: C
Solution :
[c] Since \[\alpha ,\beta \] are zeroes of the polynomial \[{{x}^{2}}+5x+c\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\alpha +\beta =-5\] ...(1) |
and \[\alpha -\beta =3\] (Given) ,..(2) |
On solving eqs. (1) and (2), we have\[\alpha =-1\] and \[\beta =-4\] |
Now, product of zeroes \[=\alpha \beta =(-1)\,(-4)=4\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,c=4\] |
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