A) \[\sqrt{2},-\sqrt{2}\]
B) \[4\sqrt{2},-2\sqrt{2}\]
C) \[-4\sqrt{2},2\sqrt{2}\]
D) \[4\sqrt{2},2\sqrt{2}\]
Correct Answer: B
Solution :
| [b] The zeroes of \[f(x)={{x}^{2}}-2\sqrt{2}x-16\] are given by |
| \[f(x)=0\]i.e., \[{{x}^{2}}-2\sqrt{2}\,\,x-16=0\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,{{x}^{2}}-4\sqrt{2}\,\,x+2\sqrt{2}\,\,x-16=0\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,x(x-4\sqrt{2})+2\sqrt{2}\,(x-4\sqrt{2})=0\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,(x+2\sqrt{2})\,\,(x-4\sqrt{2})=0\Rightarrow \,x=4\sqrt{2}\] or |
| \[x=-2\sqrt{2}\] |
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