A) 3
B) 2
C) 4
D) -2
Correct Answer: A
Solution :
| - 4 is a zero of \[{{x}^{2}}-2x-\left( 7p+3 \right)\] |
| Let \[f\left( x \right)={{x}^{2}}-2x-\left( 7p+3 \right)\] |
| \[f\left( -4 \right)=0\] |
| \[\Rightarrow \,\,0={{\left( -4 \right)}^{2}}-2\times \left( -4 \right)-\left( 7p+3 \right)\] |
| \[\Rightarrow \,0=16+8-\left( 7p+3 \right)\] |
| \[\Rightarrow \,\,7p+3=24\] |
| \[\Rightarrow \,\,7p=24-3=21\] |
| \[\therefore \,\,\,p=\frac{21}{7}=3\] |
You need to login to perform this action.
You will be redirected in
3 sec
