A) \[m,\,\,m+3\]
B) \[-m,\,\,m+3\]
C) \[m,-(\,\,m+3)\]
D) \[-m,-(\,\,m+3)\]
Correct Answer: B
Solution :
[b] Let \[f(x)={{x}^{2}}-3x-m(m+3)\] |
\[={{x}^{2}}-\{(m+3)-m\}x-m(m+3)\] |
\[={{x}^{2}}-(m+3)x+mx-m(m+3)\] |
\[=\{x-(m+3)\}+m\{x-(m+3)\}\] |
\[=\{x-(m+3)\}(x+m)\] |
For zeroes of \[f(x),\] |
\[\{x-(m+3)\}\,(x+m)=0\] |
\[x-(m+3)=0\] or \[x+m=0\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x=-m,(m+3)\] |
You need to login to perform this action.
You will be redirected in
3 sec