A) \[-3\]
B) \[3\]
C) \[\frac{13}{2}\]
D) \[-\frac{13}{2}\]
Correct Answer: C
Solution :
[c] Let \[f(x)=2{{x}^{2}}-13x+6\] |
Here, |
\[\alpha +\beta =-\frac{\text{Coefficient of }\,\text{x }}{\text{Coefficient of }\,{{\text{x}}^{2}}}=-\frac{(-13)}{2}=\frac{13}{2}\] |
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