A) \[\pm 1\]
B) \[\pm \frac{1}{2}\]
C) \[\pm 2\]
D) \[\pm 3\]
Correct Answer: C
Solution :
[c] Let \[f(x)={{x}^{2}}-3ax+2{{a}^{2}}-1\] |
Given, product of zeroes =7 |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{(2{{a}^{2}}-1)}{1}=7\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2{{a}^{2}}-1=7\Rightarrow 2{{a}^{2}}=8\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{a}^{2}}=4\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,a=\pm 2\] |
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