A) \[\frac{15}{4}\]
B) \[\frac{-15}{4}\]
C) \[4\]
D) \[15\]
Correct Answer: A
Solution :
[a] Given that, \[f(x)={{x}^{2}}-x-4\] |
\[\alpha +\beta =1\] |
and \[\alpha \beta =-4\] |
We have, |
\[\frac{1}{\alpha }+\frac{1}{\beta }-\alpha \beta =\frac{\alpha +\beta }{\alpha \beta }-\alpha \beta =-\frac{1}{4}+4=\frac{15}{4}\] |
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