A) \[-1\]
B) \[1\]
C) \[0\]
D) \[-\frac{1}{2}\]
Correct Answer: B
Solution :
[b] Let \[f(x)=2{{x}^{2}}-6kx+6x-7\] |
\[=2{{x}^{2}}-6(k-1)x-7\] |
Given, one zero of \[f(x)\] is negative of the other. |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\alpha +(-\alpha )=-\left\{ \frac{-6(k-1)}{2} \right\}\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3(k-1)=0\Rightarrow \,\,k=1\] |
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