A) All daughters normal, 50% of sons colourblind
B) All daughters normal, all sons colourblind
C) 50% daughters colourblind, all sons normal
D) All daughters colourblind, all sons normal
Correct Answer: A
Solution :
[a] A colourblind father (genotype \[({{X}^{c}}Y)\]) would produce carrier daughters (genotype \[X{{X}^{c}}\]). When a carrier female (\[X{{X}^{c}}\]) marriages a normal man (XY), the types of offspring produced would be all normal daughters and half of the sons (50%) would be colourblind and the remaining half would be normal. This pattern of inheritance can be explained by the following crossYou need to login to perform this action.
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