A) \[\frac{1}{3}\]
B) \[\frac{4}{15}\]
C) \[\frac{3}{5}\]
D) \[\frac{2}{3}\]
Correct Answer: B
Solution :
| [b] Total number of all possible outcomes = 15 |
| The given number in ascending order are as follows: |
| \[\text{2,3,3},\text{5,5,5,7,7,7},\text{7,9,9,9},\text{9,9}\] |
| Here, \[n=15,\] which is odd |
| \[\therefore \] Median \[={{\left( \frac{n+1}{2} \right)}^{th}}\]observation |
| \[={{\left( \frac{15+1}{2} \right)}^{th}}\]observation \[={{8}^{th}}\]observation=7 |
| As 7 occurs 4 times. |
| So. favourable number of outcomes = 4 |
| \[\therefore \] Required probability \[=4/15\] |
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