A) \[\frac{1}{2}\]
B) \[\frac{1}{3}\]
C) \[\frac{1}{6}\]
D) \[\frac{2}{3}\]
Correct Answer: A
Solution :
[a] Total number of possible outcomes= 6 |
Favourable outcomes of getting multiple of 2 are \[\{2,4,6\}\] i.e., 3 in number. |
\[\therefore \]Required probability \[=\frac{3}{6}=\frac{1}{2}\] |
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