A) 1
B) 4
C) 5
D) 25
Correct Answer: D
Solution :
[d] If two unbiased coins are tossed simultaneously we obtained possible outcomes. |
\[HH,HT,TH,TT\] |
Hence. Total number of outcomes = 4 |
No head is obtained if the event TT occurs. |
Hence, number of favourite outcomes = 1 |
Hence. Required probability \[=\frac{1}{4}\] |
But, given probability \[=\frac{A}{B}\] |
So,\[A=1\] |
and \[B=4\] |
Therefore, \[{{(A+B)}^{2}}={{(1+4)}^{2}}={{(5)}^{2}}=25\] |
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