A) \[\frac{1}{3}\]
B) \[\frac{1}{4}\]
C) \[\frac{3}{4}\]
D) \[\frac{3}{13}\]
Correct Answer: C
Solution :
| [c] Total number of possible outcomes = 52 |
| Number of red cards or clubs \[=26+13=39\] |
| So, number of favourable outcomes = 39 |
| \[\therefore \] Required probability \[=\frac{39}{52}=\frac{3}{4}\] |
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