A) \[\frac{1}{3}\]
B) \[\frac{1}{4}\]
C) \[\frac{5}{12}\]
D) \[\frac{2}{3}\]
Correct Answer: D
Solution :
| [d] Number of black or red balls \[=\text{5}+\text{3}=\text{8}\] |
| \[\therefore \] Required probability \[=\frac{8}{12}=\frac{2}{3}\] |
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