A) \[\frac{1}{6}\]
B) \[\frac{4}{9}\]
C) \[\frac{5}{36}\]
D) \[\frac{7}{36}\]
Correct Answer: A
Solution :
[a] Total number of possible outcomes =36 |
Let E be the event that the sum of the numbers appearing on the dice is 7. |
So, favourable outcomes to E are |
\[\{(3,4),(4,3),(2,5),(5,2),(1,6),(6,1),\}\]i.e., 6 |
\[\therefore \,\,\,\,\,\,\,\,\,\,P(E)=\frac{6}{36}=\frac{1}{6}\] |
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