A) 12
B) 18
C) 24
D) 36
Correct Answer: C
Solution :
| [c] Let there be x blue balls in the bag. |
| Hence, total number of balls in the bag |
| \[=(8+x)\]and Now, \[{{p}_{1}}\] = Probability of drawing a blue ball |
| \[=\frac{x}{8+x}\] |
| and \[{{p}_{2}}=\] Probability of drawing a red ball |
| \[=\frac{8}{8+x}\] |
| It is given that, \[{{p}_{1}}=3{{p}_{2}}\] |
| \[\frac{3}{8+x}=3\times \frac{8}{(8+x)}\] |
| \[\frac{3}{8+x}=\frac{24}{8+x}\] |
| \[x=24.\] |
| Hence, there are 24 blue balls in the bag. |
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