A) \[\frac{5}{13}\]
B) \[\frac{5}{14}\]
C) \[\frac{6}{13}\]
D) \[\frac{7}{13}\]
Correct Answer: A
Solution :
| [b] There are \[14=(5+9)\] fish out of which one can be chosen in 14 ways. |
| Hence, total number of possible outcomes =13 |
| There are 5 male fish out of which are male fish can be chosen in 5 ways. |
| Hence, favourable number of elementary events = 5 |
| Hence, required probability \[=\frac{5}{14}\] |
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