A) 2
B) 3
C) 4
D) 6
Correct Answer: B
Solution :
[b] Let E be the event 'passing the test'. |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,P(E)=\frac{X}{24}\] |
Also, P (not passing the test) \[=P(\bar{E})=\frac{7}{8}\] |
Now, \[P(E)+P(\bar{E})=1\] |
\[\Rightarrow \,\,\,\,\,\,\frac{x}{24}+\frac{7}{8}=1\Rightarrow \frac{x}{24}=1-\frac{7}{8}\Rightarrow x=\frac{24}{8}=3\] |
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