A) \[\frac{1}{13}\]
B) \[\frac{1}{52}\]
C) \[\frac{1}{26}\]
D) \[\frac{1}{2}\]
Correct Answer: A
Solution :
[a] Number of favrouable outcomes |
\[(y,z)=2\] |
Number of all possible outcomes = 26\[\therefore \] Required probability \[=\frac{2}{26}=\frac{1}{13}\]. |
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