A) \[\frac{5}{6}\]
B) \[\frac{1}{6}\]
C) \[\frac{1}{3}\]
D) None of these
Correct Answer: B
Solution :
[b] Total no. of sample outcomes \[=6\times 6=36\] |
Favourable outcomes |
\[\{(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)\}\] |
\[\therefore \] Total no. of favourable outcomes =3 |
So. required probability \[=\frac{6}{36}=\frac{1}{6}.\] |
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