A) \[\frac{1}{5}\]
B) \[\frac{1}{3}\]
C) \[\frac{7}{15}\]
D) \[\frac{8}{15}\]
Correct Answer: B
Solution :
[b] Total no. of balls |
\[=\text{3 red}+\text{5 white}+\text{7 black}=\text{15}\] |
and total no of favourable outcomes |
= Neither red nor black balls |
\[=15-(3+7)=15-10=5\] |
\[\therefore \] Required probability \[=\frac{5}{15}=\frac{1}{3}\] |
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