A) \[\frac{2}{3}\]
B) \[\frac{1}{3}\]
C) \[\frac{1}{2}\]
D) \[\frac{1}{6}\]
Correct Answer: C
Solution :
| [c] Total number of possible outcomes are = 6 |
| Favourable outcomes are \[\{2,3,5\}\] i.e.. 3 |
| \[\therefore \] P(getting a prime number) \[=\frac{3}{6}=\frac{1}{2}\] |
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