A) 1
B) 4
C) 5
D) 25
Correct Answer: D
Solution :
If two unbiased coins are tossed simultaneously we obtain possible outcomes. HH, HT, TH, TT \[\therefore \]Total number of outcomes = 4 No head is obtained if the event TT occurs. \[\therefore \]Number of favourable outcomes = 1 \[\therefore \] Required probality \[=\frac{1}{4}\] But, given probability \[=\frac{A}{B}\] So, \[A=1\] and B= 4 Therefore, \[{{\left( A+B \right)}^{2}}={{\left( 1+4 \right)}^{2}}\] \[={{\left( 5 \right)}^{2}}=25\]You need to login to perform this action.
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