A) \[\frac{1}{10}\]
B) \[\frac{3}{10}\]
C) \[\frac{7}{10}\]
D) \[\frac{9}{10}\]
Correct Answer: B
Solution :
[b] Total number of possible outcomes =10 Sum of the given numbers |
\[=2+4+4+6+6+8+8+8+8=60\] |
\[\therefore \] Average \[=\frac{\text{Sum of all the given numbers}}{\text{Total numbers}}=\frac{60}{10}=6\] |
6 occurs 3 times. |
So. favourable number of outcomes = 3 |
\[\therefore \] Required probability \[=\frac{3}{10}\] |
You need to login to perform this action.
You will be redirected in
3 sec