A) \[1/2\]
B) 2
C) \[5/6\]
D) \[7/12\]
Correct Answer: C
Solution :
[c] Total number of balls = 41 |
Now, \[x+2x+3x=24\Rightarrow 6x=24\Rightarrow x=4\] |
\[\therefore \] Number of red balls \[=x=4,\] |
Number of white balls \[=2x=8,\] |
Number of blue balls \[=3x=12,\] |
Total number of possible outcomes = 24 |
Let E be the event that the ball drawn is white or blue. |
\[\therefore \] Number of outcomes fabourable to |
\[\text{E}=\text{8}+\text{12}=\text{2}0\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,P(E)=\frac{20}{24}=\frac{5}{6}\] |
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