A) \[\frac{3}{7}\]
B) \[\frac{2}{7}\]
C) \[\frac{1}{7}\]
D) None of these
Correct Answer: A
Solution :
[a] Given numbers are \[-3,-2,-1,0,1,2,4,3.\] |
So. total possible outcomes = 7 |
Now. favourable outcomes \[({{x}^{2}}<4)=-1,0,1\] |
So, total no. of favourable outcomes =3. |
\[\therefore \]Probability \[({{x}^{2}}<4)=\frac{\text{TotaL not of fav}\text{.outcomes}}{\text{Total possible outcomes}}=\frac{3}{7}\] |
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