A) \[\frac{1}{18}\]
B) \[\frac{5}{18}\]
C) \[\frac{7}{18}\]
D) \[\frac{13}{18}\]
Correct Answer: D
Solution :
| [d] Let total score less than or equal to 5. |
| Number of favourable event |
| \[\therefore \]Number of favourable outcome so that sum is more than\[\text{5}=\text{36}-\text{1}0=\text{26}\]. |
| Required probability \[=\frac{26}{36}=\frac{13}{18}\] |
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