A) \[\frac{2}{7}\]
B) \[\frac{3}{7}\]
C) \[\frac{5}{7}\]
D) None of these
Correct Answer: C
Solution :
| [c] A leap year has 52 Sunday and 2 other days. they may be Sunday-Monday. Monday-Tuesday, Tue-wed. Wed-Thur. |
| \[\therefore \] No. of all possible outcomes =7 |
| Here. two cases out of seven have Sundays |
| i.e., Sunday-Monday or Saturday-Sunday. |
| If these two days are known then No. of Sundays would be 53. So leave these cases from possible outcomes and get favourable outcomes. |
| \[\therefore \] No. of favourable outcomes \[=7-2=5\] |
| So, Probability \[=\frac{\text{No}.\text{ of fav}.\text{ outcomes}}{\text{All possible outcomes}}=\frac{5}{7}\] |
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